From a5997063544ec9a472333dcc61cef8df54a4b039 Mon Sep 17 00:00:00 2001 From: QLWeilcf <1226824818@qq.com> Date: Sat, 13 Apr 2019 01:02:25 +0800 Subject: [PATCH 01/25] Update lcfleetcode.md --- actionCodes@QLWeilcf/lcfleetcode.md | 60 ++++++++++++++++++++++++++++- 1 file changed, 59 insertions(+), 1 deletion(-) diff --git a/actionCodes@QLWeilcf/lcfleetcode.md b/actionCodes@QLWeilcf/lcfleetcode.md index 8613b4d..b0a0f19 100644 --- a/actionCodes@QLWeilcf/lcfleetcode.md +++ b/actionCodes@QLWeilcf/lcfleetcode.md @@ -721,8 +721,66 @@ def dfs(self, nums, target, index, path, res): matrix[r][q] = matrix[p][r] matrix[p][r] = cache ``` +## 37. Sudoku Solver +- 2019-04-13 - +必须独立解出来的题； +```python +class Solution(object): + def solveSudoku(self, board): + """ + :type board: List[List[str]] + :rtype: None Do not return anything, modify board in-place instead. + """ + self.board = board + self.solve() + + def findUnassigned(self): + for row in range(9): + for col in range(9): + if self.board[row][col] == ".": + return row, col + return -1, -1 + + def solve(self): + row, col = self.findUnassigned() + #no unassigned position is found, puzzle solved + if row == -1 and col == -1: + return True + for num in ["1","2","3","4","5","6","7","8","9"]: + if self.isSafe(row, col, num): + self.board[row][col] = num + if self.solve(): + return True + self.board[row][col] = "." + return False + + def isSafe(self, row, col, ch): + boxrow = row - row%3 + boxcol = col - col%3 + if self.checkrow(row,ch) and self.checkcol(col,ch) and self.checksquare(boxrow, boxcol, ch): + return True + return False + + def checkrow(self, row, ch): + for col in range(9): + if self.board[row][col] == ch: + return False + return True + + def checkcol(self, col, ch): + for row in range(9): + if self.board[row][col] == ch: + return False + return True + + def checksquare(self, row, col, ch): + for r in range(row, row+3): + for c in range(col, col+3): + if self.board[r][c] == ch: + return False + return True +``` ## 42. Trapping Rain Water From 30a534aad2d42470d1db4871d6cad14e18cd706a Mon Sep 17 00:00:00 2001 From: QLWeilcf <1226824818@qq.com> Date: Sun, 14 Apr 2019 00:24:12 +0800 Subject: [PATCH 02/25] Update lcfleetcode.md --- actionCodes@QLWeilcf/lcfleetcode.md | 39 +++++++++++++++++++++++++++++ 1 file changed, 39 insertions(+) diff --git a/actionCodes@QLWeilcf/lcfleetcode.md b/actionCodes@QLWeilcf/lcfleetcode.md index b0a0f19..27d6e04 100644 --- a/actionCodes@QLWeilcf/lcfleetcode.md +++ b/actionCodes@QLWeilcf/lcfleetcode.md @@ -781,6 +781,45 @@ class Solution(object): return False return True ``` +## 47. Permutations II +- 2019-04-14 + +和46题的区别是这次输入可以包含重复的数字，例如可以输入`[1,1,2]`，有更巧妙的解法，但暴力法是用46题的递归然后对生成的结果去重（最后去重或每次递归都去重） + +```python +class Solution(object): + def permuteUnique(self, nums): + """ + :type nums: List[int] + :rtype: List[List[int]] + """ + n=len(nums) + if n<=1: + return [nums] + elif n==2: #注意这部分输入的坑 + if nums[0]==nums[1]: + return [nums] + return [[nums[0],nums[1]],[nums[1],nums[0]]] + kk=[] + for i in range(n): + nlst=nums[0:i]+nums[i+1:] + c=self.permuteUnique(nlst) + ss=[] + for j in c: + w=[nums[i]] + w.extend(j) + ss.append(w) + kk.extend(ss) + ks=[] + for k in kk: + if k not in ks: + ks.append(k) + kk=ks + return kk +``` + + + ## 42. Trapping Rain Water From c6e85606a49786d626d8aaf72f5da377cd056257 Mon Sep 17 00:00:00 2001 From: xkx Date: Sun, 14 Apr 2019 23:36:05 +0800 Subject: [PATCH 03/25] add sort --- .../basic_theory/sort/bubble_sort.py | 19 ++++++++++++ .../basic_theory/sort/insert_sort.py | 14 +++++++++ .../basic_theory/sort/merge_sort.py | 24 ++++++++++++++++ .../basic_theory/sort/quick_sort.py | 22 ++++++++++++++ code@xukaixuan/basic_theory/sort/readme.md | 27 ++++++++++++++++++ .../basic_theory/sort/select_sort.py | 10 +++++++ ...3\347\244\272\346\204\217\345\233\276.jpg" | Bin 0 -> 141191 bytes 7 files changed, 116 insertions(+) create mode 100644 code@xukaixuan/basic_theory/sort/bubble_sort.py create mode 100644 code@xukaixuan/basic_theory/sort/insert_sort.py create mode 100644 code@xukaixuan/basic_theory/sort/merge_sort.py create mode 100644 code@xukaixuan/basic_theory/sort/quick_sort.py create mode 100644 code@xukaixuan/basic_theory/sort/readme.md create mode 100644 code@xukaixuan/basic_theory/sort/select_sort.py create mode 100644 "code@xukaixuan/basic_theory/sort/\345\275\222\345\271\266\344\270\216\345\277\253\351\200\237\346\216\222\345\272\217\345\214\272\345\210\253\347\244\272\346\204\217\345\233\276.jpg" diff --git a/code@xukaixuan/basic_theory/sort/bubble_sort.py b/code@xukaixuan/basic_theory/sort/bubble_sort.py new file mode 100644 index 0000000..b82c552 --- /dev/null +++ b/code@xukaixuan/basic_theory/sort/bubble_sort.py @@ -0,0 +1,19 @@ +def bubble_sort(arr): + swapped = True + x = -1 + while swapped: + swap = False + x += 1 + for i in range(1, n - x): + if arr[i - 1] > arr[i]: + arr[i - 1], arr[i] = arr[i], arr[i - 1] + swapped = True + + return arr + + +def test(): + print(bubble_sort([1, 3, 4, 6, 0, 1, 4, 2])) + + +test() diff --git a/code@xukaixuan/basic_theory/sort/insert_sort.py b/code@xukaixuan/basic_theory/sort/insert_sort.py new file mode 100644 index 0000000..826893a --- /dev/null +++ b/code@xukaixuan/basic_theory/sort/insert_sort.py @@ -0,0 +1,14 @@ +def insert_sort(arr): + """ + 每次循环迭代中，插入排序从数组中删除一个元素。 + 然后再一个已经有序的数组中找到该元素的位置，并将其插入其中。 + """ + for i in range(len(arr)): + cur = arr[i] + pos = i + + while pos >0 and arr[pos-1] > cur: + arr[pos] = arr[pos-1] + pos = pos -1 + arr[pos] = cur + return arr diff --git a/code@xukaixuan/basic_theory/sort/merge_sort.py b/code@xukaixuan/basic_theory/sort/merge_sort.py new file mode 100644 index 0000000..e0ed14f --- /dev/null +++ b/code@xukaixuan/basic_theory/sort/merge_sort.py @@ -0,0 +1,24 @@ +""" + +""" +def merge_sort(arr): + if len(arr)<= 1: + return arr + mid = len(arr)//2 + left,right = merge_sort(arr[:mid]),merge_sort(arr[mid:]) + return merge(left,right,arr.copy()) + +def merge(left,right,merged): + l_cur,r_cur = 0,0 + while l_cur= end: + return + pivot_idx = partition(array, begin, end) + quick_sort_recursion(array,begin,pivot_idx-1) + quick_sort_recursion(array,pivot_idx+1,end) + + +def quick_sort(arrar): + return quick_sort_recursion(arrar,0,len(arrar)-1) diff --git a/code@xukaixuan/basic_theory/sort/readme.md b/code@xukaixuan/basic_theory/sort/readme.md new file mode 100644 index 0000000..a931708 --- /dev/null +++ b/code@xukaixuan/basic_theory/sort/readme.md @@ -0,0 +1,27 @@ +# 排序算法 +## 冒泡排序 + + 冒泡排序属于原地排序算法，空间复杂度为**O(1)** + + 冒泡排序属于**稳定排序**（相同值时，两元素的相对位置不变） + + 时间复杂度为**O(n2)** +## 插入排序 + + 插入排序是原地排序，空间复杂度为O(1) + + 插入排序属于**稳定排序** + + 插入排序时间复杂度为**O(n2)** + +## 选择排序 ++ 选择排序属于原地排序，空间复杂度为**O(1)** ++ 选择排序**不属于稳定排序** ++ 选择排序的时间复杂度为为**O(n2)** + +## 归并排序 ++ 归并排序是稳定的排序算法 ++ 归并排序的时间复杂度为O(nlogn) ++ 空间复杂度为O(n) + +## 快速排序 ++ 原地排序算法，空间复杂度为O(1)_优于归并排序_ ++ 时间复杂度为O(nlogn) ++ 稳定排序算法 + + +归并排序，与快速排序都是用分治思想，其区别可参考！[归并排序与快速排序区别](归并与快速排序区别示意图.jpg) \ No newline at end of file diff --git a/code@xukaixuan/basic_theory/sort/select_sort.py b/code@xukaixuan/basic_theory/sort/select_sort.py new file mode 100644 index 0000000..cf0684f --- /dev/null +++ b/code@xukaixuan/basic_theory/sort/select_sort.py @@ -0,0 +1,10 @@ +def select_sort(arr): + for i in range(len(arr)): + minum = i + for j in range(i+1,len(arr)): + if arr[j] < arr(minum): + minum = j + arr[minum] ,arr[i] = arr[i],arr[minum] + return arr + +print(select_sort([0,1,8,3,4,6,3,5])) diff --git "a/code@xukaixuan/basic_theory/sort/\345\275\222\345\271\266\344\270\216\345\277\253\351\200\237\346\216\222\345\272\217\345\214\272\345\210\253\347\244\272\346\204\217\345\233\276.jpg" "b/code@xukaixuan/basic_theory/sort/\345\275\222\345\271\266\344\270\216\345\277\253\351\200\237\346\216\222\345\272\217\345\214\272\345\210\253\347\244\272\346\204\217\345\233\276.jpg" new file mode 100644 index 0000000000000000000000000000000000000000..3ac31ab4e0a4896da8fef9ae5caf6ea904fbf0e7 GIT binary patch literal 141191 zcmeFZWmH^Umo8ekL-0V5BtUQo?hxDp1h?RB!5xa=PT>Ry6bTRa32`m672UOt|`PI_DcL;%oGQU7`&H+19+0~-Sa9UTJ~3kwq)9~U1V4;K%QfRN+~ z0U#6f=k2YHZ!qoAUrqoHH{B@YU!?_a_aqhq|_!6cE^#IkTFeaRb&O(v7_ zrM4S~flmuUZs{?FOToy$$prmNq<={CpA#tTe@UW$6X@UMd0YnIqoE)t42>8d1-KWe 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zbeW_w8X;)U~#pB4T-?h?=1&iNo#lL-9I}z~c(%*^W zIM#O$EvAnX>O7cUDCEnx!B{lTVa!ij7tRl?80XNG>MC;$Aqo<&LsldM_NlQD&dt&P741RLw0E#P7)$~Cs18Aw_Pr{Jf@ol}bs zO5Ql}Ff zuiIAoH6fsvKE{Y5KIdaJpe0P42a?uaTE%sG`1c>GXFcqbI;a_j{s8?KJpu3UtV%p$ z`$xTjua0~_qSN*dKmNaXHU1|N(EsjvqD*T#t+szgll=3a`qvYFsgM6RWvPFS* Date: Sun, 14 Apr 2019 23:38:29 +0800 Subject: [PATCH 04/25] Update readme.md --- code@xukaixuan/basic_theory/sort/readme.md | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/code@xukaixuan/basic_theory/sort/readme.md b/code@xukaixuan/basic_theory/sort/readme.md index a931708..dc58adb 100644 --- a/code@xukaixuan/basic_theory/sort/readme.md +++ b/code@xukaixuan/basic_theory/sort/readme.md @@ -24,4 +24,4 @@ + 稳定排序算法 -归并排序，与快速排序都是用分治思想，其区别可参考！[归并排序与快速排序区别](归并与快速排序区别示意图.jpg) \ No newline at end of file +归并排序，与快速排序都是用分治思想，其区别可参考 ![归并排序与快速排序区别](归并与快速排序区别示意图.jpg) From 55db911795df754bf2355602794bd46506a61c1b Mon Sep 17 00:00:00 2001 From: QLWeilcf <1226824818@qq.com> Date: Mon, 15 Apr 2019 00:47:16 +0800 Subject: [PATCH 05/25] Update lcfleetcode.md --- actionCodes@QLWeilcf/lcfleetcode.md | 25 +++++++++++++++++++++++++ 1 file changed, 25 insertions(+) diff --git a/actionCodes@QLWeilcf/lcfleetcode.md b/actionCodes@QLWeilcf/lcfleetcode.md index 27d6e04..d396a60 100644 --- a/actionCodes@QLWeilcf/lcfleetcode.md +++ b/actionCodes@QLWeilcf/lcfleetcode.md @@ -817,7 +817,32 @@ class Solution(object): kk=ks return kk ``` +## 50. Pow(x, n) +- 2019-04-15 +自己去实现乘方。因为输入的n是包含负数且到2^31-1，还是需要考虑边界和超限的，在Python里这些问题比较容易解决。说回实现上，暴力法是直接循环n次算乘法，我知道还有递推公式，只记得了偶数`x^n=x^{n/2}*x^{n/2}`；奇数`x^n=x^{n/2}*x^{n/2}*x`；在《编程之美》里还有迭代法，之后再研究。 +```python +class Solution(object): + def myPow(self, x, n): + if n==0: + return 1 + elif n==1: + return x + npow=True if n<0 else False + if npow: #负数的情况，只需要在递归的最后一次变成倒数就好，递归里面用正数算 + n=-n + kx=self.myPow(x,n//2) + if n%2==0:#偶数 + return 1/(kx*kx) + else: + return 1/(kx*kx*x) + else: + kx=self.myPow(x,n//2) + if n%2==0:#偶数 + return kx*kx + else: + return kx*kx*x +``` From f7df9dac6da69a9bbe0f313603abe4fb747eeed7 Mon Sep 17 00:00:00 2001 From: QLWeilcf <1226824818@qq.com> Date: Tue, 16 Apr 2019 01:23:24 +0800 Subject: [PATCH 06/25] Update lcfleetcode.md --- actionCodes@QLWeilcf/lcfleetcode.md | 48 +++++++++++++++++++++++++++++ 1 file changed, 48 insertions(+) diff --git a/actionCodes@QLWeilcf/lcfleetcode.md b/actionCodes@QLWeilcf/lcfleetcode.md index d396a60..8b2eb96 100644 --- a/actionCodes@QLWeilcf/lcfleetcode.md +++ b/actionCodes@QLWeilcf/lcfleetcode.md @@ -843,6 +843,54 @@ class Solution(object): else: return kx*kx*x ``` +## 35. Search Insert Position +- 2019-04-16 + +排序数组，显然最优是用二分； + +```python +class Solution(object): + def searchInsert(self, nums, target): + if target > nums[len(nums) - 1]: + return len(nums) + + if target < nums[0]: + return 0 + + l, r = 0, len(nums) - 1 + while l <= r: + m = (l + r)/2 + if nums[m] > target: + r = m - 1 + if r >= 0: + if nums[r] < target: + return r + 1 + else: + return 0 + + elif nums[m] < target: + l = m + 1 + if l < len(nums): + if nums[l] > target: + return l + else: + return len(nums) + else: + return m +``` +在评论区发现一些很神奇的解法：一行：`return len([x for x in nums if x Date: Wed, 17 Apr 2019 00:41:16 +0800 Subject: [PATCH 07/25] Update lcfleetcode.md --- actionCodes@QLWeilcf/lcfleetcode.md | 22 ++++++++++++++++++++++ 1 file changed, 22 insertions(+) diff --git a/actionCodes@QLWeilcf/lcfleetcode.md b/actionCodes@QLWeilcf/lcfleetcode.md index 8b2eb96..5cf7baf 100644 --- a/actionCodes@QLWeilcf/lcfleetcode.md +++ b/actionCodes@QLWeilcf/lcfleetcode.md @@ -887,8 +887,30 @@ except: nums.sort() #O(nlog(n)) return nums.index(target) ``` +## 19. Remove Nth Node From End of List +- 2019-04-17 +链表题，复杂度不高，但要实现很高效也比较有挑战 +```python +class Solution(object): + def removeNthFromEnd(self, head, n): + """ + :type head: ListNode + :type n: int + :rtype: ListNode + """ + fast = slow = head + for _ in range(n): + fast = fast.next + if not fast: + return head.next + while fast.next: + fast = fast.next + slow = slow.next + slow.next = slow.next.next + return head +``` From eafeabe465f1c99b75b0c79ac5b76c95da9ea937 Mon Sep 17 00:00:00 2001 From: QLWeilcf <1226824818@qq.com> Date: Thu, 18 Apr 2019 00:42:08 +0800 Subject: [PATCH 08/25] Update lcfleetcode.md --- actionCodes@QLWeilcf/lcfleetcode.md | 63 +++++++++++++++++++++++++++++ 1 file changed, 63 insertions(+) diff --git a/actionCodes@QLWeilcf/lcfleetcode.md b/actionCodes@QLWeilcf/lcfleetcode.md index 5cf7baf..9c0df12 100644 --- a/actionCodes@QLWeilcf/lcfleetcode.md +++ b/actionCodes@QLWeilcf/lcfleetcode.md @@ -911,8 +911,71 @@ class Solution(object): slow.next = slow.next.next return head ``` +## 56. Merge Intervals +- 2019-04-18 +合并区间，不排序的话就需要每次比较时往前看（一个while或for循环在一个for循环里），需要O(n^2)，因此还是排序吧，根据首个元素排序后的判断就容易了 +```python +class Solution(object): + def merge(self, intervals): + """ + :type intervals: List[List[int]] + :rtype: List[List[int]] + """ + if not intervals: + return [] + intervals=sorted(intervals,key=lambda j:j[0]) + res=[] + cur=intervals[0] + res.append(cur) + for i in intervals: + if res[-1][1]>=i[0] and res[-1][1] Date: Fri, 19 Apr 2019 00:48:14 +0800 Subject: [PATCH 09/25] Update lcfleetcode.md --- actionCodes@QLWeilcf/lcfleetcode.md | 34 ++++++++++++++++++++++++++++- 1 file changed, 33 insertions(+), 1 deletion(-) diff --git a/actionCodes@QLWeilcf/lcfleetcode.md b/actionCodes@QLWeilcf/lcfleetcode.md index 9c0df12..6fa5bb8 100644 --- a/actionCodes@QLWeilcf/lcfleetcode.md +++ b/actionCodes@QLWeilcf/lcfleetcode.md @@ -976,13 +976,45 @@ class Solution(object): j += dj return A ``` +## 38. Count and Say +- 2019-04-19 + +这是个easy题，还是很巧妙的，计算n时n-1情况下值的计数形成一个新数（返回值为str类型），n取决于n-1，所以有递推，推导出递推式子后写递归。关键是统计出连续的值有多少个，在连续时，count，不连续时换新的count。 +```python +class Solution(object): + def countAndSay(self, n): + if n==1: #终止条件 + return '1' + res='' + nm=self.countAndSay(n-1) + k=len(nm) + cv=[nm[0],0] #当前计数的值 可以用dict {nm[0]:0} + for i in nm: + if i==cv[0]: + cv[1]=cv[1]+1 + else: #不连续时，记录之前的状态+重置cv + res='{0}{1}{2}'.format(res,cv[1],cv[0]) + cv=[i,1] + res='{0}{1}{2}'.format(res,cv[1],cv[0]) + return res + +``` + + + + + + + + + ## 42. Trapping Rain Water -这题2018年在面试中遇到过，当时想了好久才推出递归写法，早就后悔没多刷题了，看到这题更后悔没早点多刷题了。 +这题2018年在面试中遇到过，当时想了好久才推出递归写法，早就后悔没多刷题了，看到这题更后悔没早点多刷题了。不愧是第42题。 ```python # 等我找到我以前的解法 From 1588e3b027c3f2d5a731a342c9ff904de511192d Mon Sep 17 00:00:00 2001 From: QLWeilcf <1226824818@qq.com> Date: Sat, 20 Apr 2019 00:21:05 +0800 Subject: [PATCH 10/25] Update lcfleetcode.md --- actionCodes@QLWeilcf/lcfleetcode.md | 12 ++++++++++++ 1 file changed, 12 insertions(+) diff --git a/actionCodes@QLWeilcf/lcfleetcode.md b/actionCodes@QLWeilcf/lcfleetcode.md index 6fa5bb8..ce56a41 100644 --- a/actionCodes@QLWeilcf/lcfleetcode.md +++ b/actionCodes@QLWeilcf/lcfleetcode.md @@ -999,7 +999,19 @@ class Solution(object): return res ``` +## 62. Unique Paths +- 2019-04-20 +这是很有趣的题，用动规解，记得可以推出一个规则的。 +```python +class Solution(object): + def uniquePaths(self, m, n): + dp = [1] * n + for i in range(1, m): + for j in range(1, n): + dp[j] = dp[j - 1] + dp[j] + return dp[-1] if m and n else 0 +``` From abed4fefc0de143c381553d8abfe525444f30a40 Mon Sep 17 00:00:00 2001 From: QLWeilcf <1226824818@qq.com> Date: Sun, 21 Apr 2019 00:39:03 +0800 Subject: [PATCH 11/25] Update lcfleetcode.md --- actionCodes@QLWeilcf/lcfleetcode.md | 24 ++++++++++++++++++++++++ 1 file changed, 24 insertions(+) diff --git a/actionCodes@QLWeilcf/lcfleetcode.md b/actionCodes@QLWeilcf/lcfleetcode.md index ce56a41..9a0a299 100644 --- a/actionCodes@QLWeilcf/lcfleetcode.md +++ b/actionCodes@QLWeilcf/lcfleetcode.md @@ -1012,6 +1012,30 @@ class Solution(object): dp[j] = dp[j - 1] + dp[j] return dp[-1] if m and n else 0 ``` +## 64. Minimum Path Sum +- 2019-04-21 + +这种全局最优显然要考虑递归，类似背包问题。 +```python +class Solution(object): + def minPathSum(self, grid): + """ + :type grid: List[List[int]] + :rtype: int + """ + c,r = len(grid),len(grid[0]) + for i in range(c): + for j in range(r): + if i ==0 and j ==0: + continue + elif i == 0: + grid[i][j] += grid[i][j-1] + elif j == 0: + grid[i][j] += grid[i-1][j] + else: + grid[i][j] += min(grid[i][j-1], grid[i-1][j]) + return grid[-1][-1] +``` From 0ef0e68c3a780f8484a286a41f5ee1a4366ce7f3 Mon Sep 17 00:00:00 2001 From: QLWeilcf <1226824818@qq.com> Date: Mon, 22 Apr 2019 23:05:46 +0800 Subject: [PATCH 12/25] Update lcfleetcode.md --- actionCodes@QLWeilcf/lcfleetcode.md | 15 +++++++++++++++ 1 file changed, 15 insertions(+) diff --git a/actionCodes@QLWeilcf/lcfleetcode.md b/actionCodes@QLWeilcf/lcfleetcode.md index 9a0a299..a5f437c 100644 --- a/actionCodes@QLWeilcf/lcfleetcode.md +++ b/actionCodes@QLWeilcf/lcfleetcode.md @@ -1036,7 +1036,22 @@ class Solution(object): grid[i][j] += min(grid[i][j-1], grid[i-1][j]) return grid[-1][-1] ``` +## 53. Maximum Subarray +- 2019-04-22 +这题乍看上去需要循环尝试很多，看到一种很厉害的解法： +```python +class Solution(object): + def maxSubArray(self, nums): + """ + :type nums: List[int] + :rtype: int + """ + for i in range(1, len(nums)): + if nums[i-1] > 0: + nums[i] += nums[i-1] + return max(nums) +``` From 3821ea47a43dbc8001564f67ad386fb5cfb7e1b3 Mon Sep 17 00:00:00 2001 From: QLWeilcf <1226824818@qq.com> Date: Tue, 23 Apr 2019 00:25:53 +0800 Subject: [PATCH 13/25] Update lcfleetcode.md --- actionCodes@QLWeilcf/lcfleetcode.md | 31 +++++++++++++++++++++++++++++ 1 file changed, 31 insertions(+) diff --git a/actionCodes@QLWeilcf/lcfleetcode.md b/actionCodes@QLWeilcf/lcfleetcode.md index a5f437c..6f327e5 100644 --- a/actionCodes@QLWeilcf/lcfleetcode.md +++ b/actionCodes@QLWeilcf/lcfleetcode.md @@ -1052,7 +1052,38 @@ class Solution(object): nums[i] += nums[i-1] return max(nums) ``` +## 74. Search a 2D Matrix +- 2019-04-23 + +简单搜索比较容易，O(log(n))解法还是挺难想的： +``` +class Solution(object): + def searchMatrix(self, matrix, target): + """ + :type matrix: List[List[int]] + :type target: int + :rtype: bool + """ + if not matrix or target is None: + return False + + rows, cols = len(matrix), len(matrix[0]) + low, high = 0, rows * cols - 1 + + while low <= high: + mid = (low + high) / 2 + num = matrix[mid / cols][mid % cols] + + if num == target: + return True + elif num < target: + low = mid + 1 + else: + high = mid - 1 + + return False +``` From ed8ac62358add2e47c8e816030974a0e393da2d1 Mon Sep 17 00:00:00 2001 From: QLWeilcf <1226824818@qq.com> Date: Wed, 24 Apr 2019 10:40:40 +0800 Subject: [PATCH 14/25] Update lcfleetcode.md --- actionCodes@QLWeilcf/lcfleetcode.md | 29 +++++++++++++++++++++++++++++ 1 file changed, 29 insertions(+) diff --git a/actionCodes@QLWeilcf/lcfleetcode.md b/actionCodes@QLWeilcf/lcfleetcode.md index 6f327e5..35f4b5c 100644 --- a/actionCodes@QLWeilcf/lcfleetcode.md +++ b/actionCodes@QLWeilcf/lcfleetcode.md @@ -1084,8 +1084,37 @@ class Solution(object): return False ``` +## 77. Combinations +- 2019-04-24 +组合，实现C{n,m}，itertools里有轮子combinations +``` +if k == 0: + return [[]] + return [pre + [i] for i in range(k, n+1) for pre in self.combine(i-1, k-1)] +``` +可能更好理解些： +``` +class Solution: + def combine(self, n, k): + stack = [] + res = [] + l, x = 0, 1 + while True: + + if l == k: + res.append(stack[:]) + if l == k or n-x+1 < k-l: + if not stack: + return res + x = stack.pop() + 1 + l -= 1 + else: + stack.append(x) + x += 1 + l += 1 +``` From 5ea9f40872ccec366bed3e47c6280b4649125035 Mon Sep 17 00:00:00 2001 From: QLWeilcf <1226824818@qq.com> Date: Thu, 25 Apr 2019 00:58:21 +0800 Subject: [PATCH 15/25] Update lcfleetcode.md --- actionCodes@QLWeilcf/lcfleetcode.md | 18 ++++++++++++++++++ 1 file changed, 18 insertions(+) diff --git a/actionCodes@QLWeilcf/lcfleetcode.md b/actionCodes@QLWeilcf/lcfleetcode.md index 35f4b5c..b0c5e9f 100644 --- a/actionCodes@QLWeilcf/lcfleetcode.md +++ b/actionCodes@QLWeilcf/lcfleetcode.md @@ -1115,7 +1115,25 @@ class Solution: x += 1 l += 1 ``` +## 66. Plus One +- 2019-04-25 +easy题 +```python +class Solution(object): + def plusOne(self, digits): + digits[-1] += 1 + for i in range(len(digits)-1, 0, -1): + if digits[i] != 10: + break + digits[i] = 0 + digits[i-1] += 1 + + if digits[0] == 10: + digits[0] = 0 + digits.insert(0,1) + return digits +``` From 46573cd431b370549248c532ee09d86ca69a53c9 Mon Sep 17 00:00:00 2001 From: QLWeilcf <1226824818@qq.com> Date: Fri, 26 Apr 2019 00:20:17 +0800 Subject: [PATCH 16/25] Update lcfleetcode.md --- actionCodes@QLWeilcf/lcfleetcode.md | 11 +++++++++++ 1 file changed, 11 insertions(+) diff --git a/actionCodes@QLWeilcf/lcfleetcode.md b/actionCodes@QLWeilcf/lcfleetcode.md index b0c5e9f..a7a628e 100644 --- a/actionCodes@QLWeilcf/lcfleetcode.md +++ b/actionCodes@QLWeilcf/lcfleetcode.md @@ -1134,7 +1134,18 @@ class Solution(object): digits.insert(0,1) return digits ``` +## 78. Subsets +- 2019-04-26 +求一个集合的所有子集， +```python +class Solution(object): + def subsets(self, nums): + res = [[]] + for num in sorted(nums): + res =res+ [item+[num] for item in res] + return res +``` From b9c5e8580a1d8ad51c4e74548fb5221b4f121ae0 Mon Sep 17 00:00:00 2001 From: QLWeilcf <1226824818@qq.com> Date: Sat, 27 Apr 2019 00:12:47 +0800 Subject: [PATCH 17/25] Update lcfleetcode.md --- actionCodes@QLWeilcf/lcfleetcode.md | 13 +++++++++++++ 1 file changed, 13 insertions(+) diff --git a/actionCodes@QLWeilcf/lcfleetcode.md b/actionCodes@QLWeilcf/lcfleetcode.md index a7a628e..5023219 100644 --- a/actionCodes@QLWeilcf/lcfleetcode.md +++ b/actionCodes@QLWeilcf/lcfleetcode.md @@ -1146,7 +1146,20 @@ class Solution(object): res =res+ [item+[num] for item in res] return res ``` +## 80. Remove Duplicates from Sorted Array II +- 2019-04-27 +要在O(1)空间内实现，就靠循环和if了； +```python +class Solution(object): + def removeDuplicates(self, nums): + i = 0 + for n in nums: + if i < 2 or n > nums[i-2]: + nums[i] = n + i += 1 + return i +``` From ec8ac795556f316fa0b3c4b88557a31c5078fd6c Mon Sep 17 00:00:00 2001 From: QLWeilcf <1226824818@qq.com> Date: Sun, 28 Apr 2019 22:26:55 +0800 Subject: [PATCH 18/25] Update lcfleetcode.md --- actionCodes@QLWeilcf/lcfleetcode.md | 74 +++++++++++++++++++++++++++++ 1 file changed, 74 insertions(+) diff --git a/actionCodes@QLWeilcf/lcfleetcode.md b/actionCodes@QLWeilcf/lcfleetcode.md index 5023219..fdbdf1d 100644 --- a/actionCodes@QLWeilcf/lcfleetcode.md +++ b/actionCodes@QLWeilcf/lcfleetcode.md @@ -1160,6 +1160,80 @@ class Solution(object): i += 1 return i ``` +## 67. Add Binary +- 2019-04-28 + +用二进制的进位逻辑去算，不过输入输出都是字符串，不过就0，1两种字符，不需要转int了 +```python +class Solution(object): + def addBinary(self, a, b):#按逐个进位写的巨长的代码 + na=len(a) + nb=len(b) + res=[] + rf={'0':0,'1':1} + aone=0 #进位 add new one + if na=nb + for i in range(nb): + r=rf[a[na-i-1]]+rf[b[nb-i-1]]+aone + if r==3: + res.append('1') + aone=1 + elif r==2: + res.append('0') + aone=1 + elif r==1: + res.append('1') #0 or 1 + aone=0 #? + elif r==0: + res.append('0') + aone=0 + for i in range(na-nb-1,-1,-1): + r=rf[a[i]]+aone + if r==2: + res.append('0') #aone=1 + elif r==1: + res.append('1') + aone=0 + elif r==0: + res.append('0') + aone=0 + if aone==1: + res.append('1') + ors=[] + for i in range(len(res),0,-1): + ors.append(res[i-1]) + return ''.join(ors) +``` +而看讨论区，一行代码有：`return bin(eval('0b' + a) + eval('0b' + b))[2:]`，0b means that the number that follows is in binary. `return f"{int(a,2)+int(b,2):b}"`； + + + From db784b1dfe2b5a83cade1752129ed79d68daaa1c Mon Sep 17 00:00:00 2001 From: QLWeilcf <1226824818@qq.com> Date: Mon, 29 Apr 2019 00:12:09 +0800 Subject: [PATCH 19/25] Update lcfleetcode.md --- actionCodes@QLWeilcf/lcfleetcode.md | 22 ++++++++++++++++++++++ 1 file changed, 22 insertions(+) diff --git a/actionCodes@QLWeilcf/lcfleetcode.md b/actionCodes@QLWeilcf/lcfleetcode.md index fdbdf1d..2db9023 100644 --- a/actionCodes@QLWeilcf/lcfleetcode.md +++ b/actionCodes@QLWeilcf/lcfleetcode.md @@ -1146,6 +1146,28 @@ class Solution(object): res =res+ [item+[num] for item in res] return res ``` +## 90. Subsets II +- 2019-04-29 + +和原先子集题（78）的区别是这个可以有重复元素； +```python +class Solution(object): + def subsetsWithDup(self, nums): + if not nums: + return [] + nums.sort() + res, cur = [[]], [] + for i in range(len(nums)): + if i > 0 and nums[i] == nums[i-1]: + cur = [item + [nums[i]] for item in cur] + else: + cur = [item + [nums[i]] for item in res] + res += cur + return res +``` + + + ## 80. Remove Duplicates from Sorted Array II - 2019-04-27 From 525a29dad8513a23949082e97a139d30f5626000 Mon Sep 17 00:00:00 2001 From: QLWeilcf <1226824818@qq.com> Date: Tue, 30 Apr 2019 00:52:47 +0800 Subject: [PATCH 20/25] Update lcfleetcode.md --- actionCodes@QLWeilcf/lcfleetcode.md | 7 +++++++ 1 file changed, 7 insertions(+) diff --git a/actionCodes@QLWeilcf/lcfleetcode.md b/actionCodes@QLWeilcf/lcfleetcode.md index 2db9023..94c2cdf 100644 --- a/actionCodes@QLWeilcf/lcfleetcode.md +++ b/actionCodes@QLWeilcf/lcfleetcode.md @@ -1254,7 +1254,14 @@ class Solution(object): ``` 而看讨论区，一行代码有：`return bin(eval('0b' + a) + eval('0b' + b))[2:]`，0b means that the number that follows is in binary. `return f"{int(a,2)+int(b,2):b}"`； +## 91. Decode Ways +- 2019-04-30 +有趣的题目，标个:star，之后再解。 + +```python +# todo +``` From bad245b4618fc8d1e28be3ed9b1916ce14c73361 Mon Sep 17 00:00:00 2001 From: QLWeilcf <1226824818@qq.com> Date: Wed, 1 May 2019 21:55:51 +0800 Subject: [PATCH 21/25] Update lcfleetcode.md --- actionCodes@QLWeilcf/lcfleetcode.md | 18 +++++++++++++++++- 1 file changed, 17 insertions(+), 1 deletion(-) diff --git a/actionCodes@QLWeilcf/lcfleetcode.md b/actionCodes@QLWeilcf/lcfleetcode.md index 94c2cdf..78155e2 100644 --- a/actionCodes@QLWeilcf/lcfleetcode.md +++ b/actionCodes@QLWeilcf/lcfleetcode.md @@ -1262,8 +1262,24 @@ class Solution(object): ```python # todo ``` +## 180. Consecutive Numbers +- 2019-05-01 - +五一第一天写个SQL题； +``` +SELECT DISTINCT + l1.Num AS ConsecutiveNums +FROM + Logs l1, + Logs l2, + Logs l3 +WHERE + l1.Id = l2.Id - 1 + AND l2.Id = l3.Id - 1 + AND l1.Num = l2.Num + AND l2.Num = l3.Num +; +``` From 93f27d5b43443d7e30ccdc8ca621cd82a5440770 Mon Sep 17 00:00:00 2001 From: Kaixuan Xu Date: Thu, 2 May 2019 14:29:34 +0800 Subject: [PATCH 22/25] add leetcode 56,57 about sort problem --- .../56.merge-intervals.py | 18 ++++++++++++++++++ .../demo56 merge-intervals/readme.md | 18 ++++++++++++++++++ .../57.insert-interval.py | 16 ++++++++++++++++ .../demo57 insert-intervals/readme.md | 19 +++++++++++++++++++ 4 files changed, 71 insertions(+) create mode 100644 code@xukaixuan/demo56 merge-intervals/56.merge-intervals.py create mode 100644 code@xukaixuan/demo56 merge-intervals/readme.md create mode 100644 code@xukaixuan/demo57 insert-intervals/57.insert-interval.py create mode 100644 code@xukaixuan/demo57 insert-intervals/readme.md diff --git a/code@xukaixuan/demo56 merge-intervals/56.merge-intervals.py b/code@xukaixuan/demo56 merge-intervals/56.merge-intervals.py new file mode 100644 index 0000000..28efe52 --- /dev/null +++ b/code@xukaixuan/demo56 merge-intervals/56.merge-intervals.py @@ -0,0 +1,18 @@ +# +# @lc app=leetcode id=56 lang=python3 +# +# [56] Merge Intervals +# +class Solution: + def merge(self, intervals: List[List[int]]) -> List[List[int]]: + ans = [] + for invt in sorted(intervals,key = lambda x :x[0]): + if (ans and ans[-1][-1] >= invt[0]): + ans[-1][-1] = max(invt[-1],ans[-1][-1]) + else: + ans.append(invt) + return ans + + + + diff --git a/code@xukaixuan/demo56 merge-intervals/readme.md b/code@xukaixuan/demo56 merge-intervals/readme.md new file mode 100644 index 0000000..e659a66 --- /dev/null +++ b/code@xukaixuan/demo56 merge-intervals/readme.md @@ -0,0 +1,18 @@ +## 56 Merge Intervals +### 题目描述 +Given a collection of intervals, merge all overlapping intervals. +``` +# example1 +Input: [[1,3],[2,6],[8,10],[15,18]] +Output: [[1,6],[8,10],[15,18]] +Explanation: Since intervals [1,3] and [2,6] overlaps, merge them into [1,6]. +``` + +``` +Input: [[1,4],[4,5]] +Output: [[1,5]] +Explanation: Intervals [1,4] and [4,5] are considered overlapping. +``` +### 考察知识点 + +排序 数组 \ No newline at end of file diff --git a/code@xukaixuan/demo57 insert-intervals/57.insert-interval.py b/code@xukaixuan/demo57 insert-intervals/57.insert-interval.py new file mode 100644 index 0000000..c4b89c6 --- /dev/null +++ b/code@xukaixuan/demo57 insert-intervals/57.insert-interval.py @@ -0,0 +1,16 @@ +# +# @lc app=leetcode id=57 lang=python3 +# +# [57] Insert Interval +# +class Solution: + def insert(self, intervals: List[List[int]], newInterval: List[int]) -> List[List[int]]: + s,e = newInterval[0],newInterval[-1] + left = [i for i in intervals if i[-1]e] + if left + right != intervals: + s = min(s,intervals[len(left)][0]) + e = max(e,intervals[~len(right)][-1]) + return left + [Interval(s,e)] +right + + diff --git a/code@xukaixuan/demo57 insert-intervals/readme.md b/code@xukaixuan/demo57 insert-intervals/readme.md new file mode 100644 index 0000000..a799187 --- /dev/null +++ b/code@xukaixuan/demo57 insert-intervals/readme.md @@ -0,0 +1,19 @@ +## Insert Interval +### 考察知识点 +排序 +### description +Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). + +You may assume that the intervals were initially sorted according to their start times. + +Example 1: +``` +Input: intervals = [[1,3],[6,9]], newInterval = [2,5] +Output: [[1,5],[6,9]] +``` +Example 2: +``` +Input: intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8] +Output: [[1,2],[3,10],[12,16]] +Explanation: Because the new interval [4,8] overlaps with [3,5],[6,7],[8,10]. +``` \ No newline at end of file From 4121ac5deb0c89787ffd2cb1dd5cf54f0d14b0a4 Mon Sep 17 00:00:00 2001 From: Kaixuan Xu Date: Sat, 4 May 2019 16:22:50 +0800 Subject: [PATCH 23/25] add binary search for special scenery --- code@xukaixuan/basic_theory/binary_search.js | 88 ++++++++++++++++++++ 1 file changed, 88 insertions(+) create mode 100644 code@xukaixuan/basic_theory/binary_search.js diff --git a/code@xukaixuan/basic_theory/binary_search.js b/code@xukaixuan/basic_theory/binary_search.js new file mode 100644 index 0000000..a46d846 --- /dev/null +++ b/code@xukaixuan/basic_theory/binary_search.js @@ -0,0 +1,88 @@ +/** + * 二分查找 + */ + + // 查找等于第一个给定的值 +const binaryFindFirst = (sortedArr,target) =>{ + if (sortedArr.length === 0) return -1 + let low = 0 + let high = sortedArr.length-1 + while(low <=high) { + const mid = Math.floor((low+high)/2) + + if (target < sortedArr[mid]){ + high = mid -1 + }else if (target> sortedArr[mid]){ + low = mid +1 + }else{ + if (mid ===0||sortedArr[mid-1]{ + if (sortedArr.length ===0) return -1 + let low =0 + let high = sortedArr.length-1 + while(low <=high){ + const mid = Math.floor((low+high)/2) + if (targetsortedArr[mid]){ + low = mid +1 + }else { + if (mid ===sortedArr.length -1||sortedArr[mid+1]>target) return mid + low = mid + 1 + } + } + return -1 +} + +// 查找第一个大于等于给定元素的值 +const binaryFindFiRstBig = (sortedArr,target) =>{ + if (sortedArr.length === 0) return -1 + let low = 0 + let high = sortedArr.length-1 + while(low< high){ + const mid = Math.floor((low+high)/2) + if (sortedArr[mid]{ + if (sortedArr.length === 0) return -1 + let low = 0 + let high = sortedArr.length-1 + while(low< high){ + const mid = Math.floor((low+high)/2) + if (sortedArr[mid]target) return mid + low = mid +1 + } + } +return -1 +} + +const arr = [1, 2, 3, 4, 4, 4, 4, 4, 6, 7, 8, 8, 9] +const first = biaryFindFirst(arr, 4) +console.log(`FindFirst: ${first}`) + +const last = biaryFindLast(arr, 4) +console.log(`FindLast: ${last}`) +const FisrtBig = biaryFindFistBig(arr, 5) +console.log(`FindFisrtBig: ${FisrtBig}`) +const LastSmall = biaryFindLastSmall(arr, 4) +console.log(`FindLastSmall: ${LastSmall}`) \ No newline at end of file From 6fcec96b571a40f1971e3ba43c48febedc8f73ef Mon Sep 17 00:00:00 2001 From: Kaixuan Xu Date: Mon, 6 May 2019 22:25:07 +0800 Subject: [PATCH 24/25] add demo for binary_search and refine the basic threoy for bianary_search --- code@xukaixuan/basic_theory/binary_search.js | 4 +- .../33.search-in-rotated-sorted-array.py | 34 ++++++++++ .../demo 33 binary_search/readme.md | 27 ++++++++ ...ast-position-of-element-in-sorted-array.py | 65 +++++++++++++++++++ .../demo 34 binary_search/readme.md | 26 ++++++++ 5 files changed, 154 insertions(+), 2 deletions(-) create mode 100644 code@xukaixuan/demo 33 binary_search/33.search-in-rotated-sorted-array.py create mode 100644 code@xukaixuan/demo 33 binary_search/readme.md create mode 100644 code@xukaixuan/demo 34 binary_search/34.find-first-and-last-position-of-element-in-sorted-array.py create mode 100644 code@xukaixuan/demo 34 binary_search/readme.md diff --git a/code@xukaixuan/basic_theory/binary_search.js b/code@xukaixuan/basic_theory/binary_search.js index a46d846..90f3b94 100644 --- a/code@xukaixuan/basic_theory/binary_search.js +++ b/code@xukaixuan/basic_theory/binary_search.js @@ -49,7 +49,7 @@ const binaryFindFiRstBig = (sortedArr,target) =>{ let high = sortedArr.length-1 while(low< high){ const mid = Math.floor((low+high)/2) - if (sortedArr[mid]= target){ if (mid ===0||sortedArr[mid-1]{ if (sortedArr.length === 0) return -1 let low = 0 let high = sortedArr.length-1 - while(low< high){ + while(low <= high){ const mid = Math.floor((low+high)/2) if (sortedArr[mid] int: + def search(self, nums, target): + if not nums: + return -1 + + low, high = 0, len(nums) - 1 + + while low <= high: + mid = (low + high) / 2 + if target == nums[mid]: + return mid + + if nums[low] <= nums[mid]: + if nums[low] <= target <= nums[mid]: + high = mid - 1 + else: + low = mid + 1 + else: + if nums[mid] <= target <= nums[high]: + low = mid + 1 + else: + high = mid - 1 + + return -1 + + + + diff --git a/code@xukaixuan/demo 33 binary_search/readme.md b/code@xukaixuan/demo 33 binary_search/readme.md new file mode 100644 index 0000000..0e3e3f5 --- /dev/null +++ b/code@xukaixuan/demo 33 binary_search/readme.md @@ -0,0 +1,27 @@ +## Search in Rotated Sorted Array + +Tags + +array | binary-search + +## description +Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. + +(i.e.,``` [0,1,2,4,5,6,7]``` might become ```[4,5,6,7,0,1,2]```). + +You are given a target value to search. If found in the array return its index, otherwise return -1. + +You may assume no duplicate exists in the array. + +Your algorithm's runtime complexity must be in the order of ```O(log n)```. + +``` +Example 1: + +Input: nums = [4,5,6,7,0,1,2], target = 0 +Output: 4 +Example 2: + +Input: nums = [4,5,6,7,0,1,2], target = 3 +Output: -1 +``` \ No newline at end of file diff --git a/code@xukaixuan/demo 34 binary_search/34.find-first-and-last-position-of-element-in-sorted-array.py b/code@xukaixuan/demo 34 binary_search/34.find-first-and-last-position-of-element-in-sorted-array.py new file mode 100644 index 0000000..9043625 --- /dev/null +++ b/code@xukaixuan/demo 34 binary_search/34.find-first-and-last-position-of-element-in-sorted-array.py @@ -0,0 +1,65 @@ +# +# @lc app=leetcode id=34 lang=python +# +# [34] Find First and Last Position of Element in Sorted Array +# +class Solution(object): + def searchRange(self, nums, target): + """ + :type nums: List[int] + :type target: int + :rtype: List[int] + """ + lo,hi = 0,len(nums)-1 + first,last = -1,-1 + while(lo <=hi): + mid = lo +( hi -lo)//2 + if target< nums[mid]: + hi = mid -1 + elif target > nums[mid]: + lo = mid + 1 + else : + if (mid == 0 or nums[mid-1] < target): + first = mid + hi = mid-1 + lo,hi = 0,len(nums)-1 + while(lo <= hi): + mid = lo +( hi -lo)//2 + if target< nums[mid]: + hi = mid -1 + elif target > nums[mid]: + lo = mid + 1 + else : + if (mid == len(nums)-1 or nums[mid+1] > target): + last = mid + lo = mid+1 + return [first,last] + + +## most voted + +def searchRange(self, nums, target): + def binarySearchLeft(A, x): + left, right = 0, len(A) - 1 + while left <= right: + mid = (left + right) / 2 + if x > A[mid]: left = mid + 1 + else: right = mid - 1 + return left + + def binarySearchRight(A, x): + left, right = 0, len(A) - 1 + while left <= right: + mid = (left + right) / 2 + if x >= A[mid]: left = mid + 1 + else: right = mid - 1 + return right + + left, right = binarySearchLeft(nums, target), binarySearchRight(nums, target) + return (left, right) if left <= right else [-1, -1] + + + + + + diff --git a/code@xukaixuan/demo 34 binary_search/readme.md b/code@xukaixuan/demo 34 binary_search/readme.md new file mode 100644 index 0000000..a575ace --- /dev/null +++ b/code@xukaixuan/demo 34 binary_search/readme.md @@ -0,0 +1,26 @@ +# Search Insert Position + + +## description +Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. + +You may assume no duplicates in the array. +``` +Example 1: + +Input: [1,3,5,6], 5 +Output: 2 +Example 2: + +Input: [1,3,5,6], 2 +Output: 1 +Example 3: + +Input: [1,3,5,6], 7 +Output: 4 +Example 4: + +Input: [1,3,5,6], 0 +Output: 0 +``` + From 42fc31fc5a54a7315c1d3d177dbb464adda051f1 Mon Sep 17 00:00:00 2001 From: QLWeilcf <1226824818@qq.com> Date: Sun, 24 Nov 2019 20:25:03 +0800 Subject: [PATCH 25/25] Update lcfleetcode.md --- actionCodes@QLWeilcf/lcfleetcode.md | 105 ++++++++++++++++++++++++++++ 1 file changed, 105 insertions(+) diff --git a/actionCodes@QLWeilcf/lcfleetcode.md b/actionCodes@QLWeilcf/lcfleetcode.md index 78155e2..14d0220 100644 --- a/actionCodes@QLWeilcf/lcfleetcode.md +++ b/actionCodes@QLWeilcf/lcfleetcode.md @@ -1282,7 +1282,112 @@ WHERE ``` +## 37. 解数独 +（现在上leetcode默认都跳中文官网了） +```python +class Solution: + def solveSudoku(self, board: List[List[str]]) -> None: + """ + Do not return anything, modify board in-place instead. + """ + #x,y=(0,0) if self._b[0][0]==0 else self.getNext(0,0) + if board[0][0]=='.':#更容易理解的写法 + self.trysxy(0,0,board) + else: + x,y=self.getNext(0,0,board) + self.trysxy(x,y,board) + def checkNotSame(self,x,y,val,board):#检查每行、每列及宫内是否有和b[x,y]相同项 + for row_item in board[x]: #第x行 + if row_item==val: + return False + for rows in board:#y所在列 + if rows[y]==val: + return False + ax=x//3*3 #把0~3中的值映射到[0,3] + ab=y//3*3 + for r in range(ax,ax+3): + for c in range(ab,ab+3):#注意r==x & c==y的情况下，其实没必要，val不会是0 + if board[r][c]==val: + return False + return True + def getNext(self,x,y,board): #得到下一个未填项,从x,y往下数，值等于0就返回新下标 + for ny in range(y+1,9): #下标是[0,8] + if board[x][ny]=='.': + return (x,ny) + for row in range(x+1,9): + for ny in range(0,9): + if board[row][ny]=='.': + return (row,ny) + return (-1,-1) #不存在下一个未填项的情况 + def getPrem(self,x,y,board): #得到x，y处可以填的值 + prem=[] + rows=list(board[x]) + rows.extend([board[i][y] for i in range(9)]) + cols=set(rows) + for i in range(1,10): + i=str(i) + if i not in cols: + prem.append(i) + return prem + def trysxy(self,x,y,board): #主循环，尝试x，y处的解答 + if board[x][y]=='.': #不等于0的情况在调用外处理 + pv=self.getPrem(x,y,board) + for v in pv: + if self.checkNotSame(x,y,v,board):# 符合 行列宫均满足v符合条件 的 + board[x][y]=v + nx,ny=self.getNext(x,y,board) #得到下一个0值格 + if nx==-1: #没有下一个0格了；and ny==-1可以写但没必要 + return True + else: + _end=self.trysxy(nx,ny,board) #向下尝试,递归 + if not _end: + board[x][y]='.' #回溯，继续for v循环 + #只需要改x，y处的值，不改其他值 + else: + return True +``` +回溯法，时间效率还行，因为是递归，空间耗费比较大， + +```python +class Solution: + def isValidSudoku(self, board: List[List[str]]) -> bool: + if board[0][0]!='.': + return self.check(0,0,board) + else: + nx,ny=self.getNext(0,0,board) + if nx==-1: + return True + return self.check(nx,ny,board) + def check(self,x,y,b):#检查数独是否合法 + v=b[x][y] + for r in range(0,9): + if r!=x: + if b[r][y]==v: + return False + if r!=y: + if b[x][r]==v: + return False + ax=x//3*3 + ab=y//3*3 + for r in range(ax,ax+3): + for c in range(ab,ab+3): + if b[r][c]==v and r!=x and c!=y: + return False + nx,ny=self.getNext(x,y,b) + if nx==-1: + return True + return self.check(nx,ny,b) + def getNext(self,x,y,b): + for ny in range(y+1,9): + if b[x][ny]!='.': + return (x,ny) + for r in range(x+1,9): + for ny in range(0,9): + if b[r][ny]!='.': + return (r,ny) + return (-1,-1) +``` ## 42. Trapping Rain Water