docs: apply code review feedback for Exponentiation and SQL Reformat Department Table

Author: myoshi2891

Mathematics/Exponentiation by Squaring/leetcode/50. Pow(x, n)/Claude/README detailed.html

@@ -788,21 +788,6 @@ <h3>🎯 実際の計算比較</h3>
                     .join('');
             }
 
-            // 例題の解析を表示
-            function displayExamples() {
-                // 例1
-                const ex1 = myPowWithSteps(2, 10);
-                document.getElementById('example1').innerHTML = formatSteps(ex1);
-
-                // 例2
-                const ex2 = myPowWithSteps(2.1, 3);
-                document.getElementById('example2').innerHTML = formatSteps(ex2);
-
-                // 例3
-                const ex3 = myPowWithSteps(2, -2);
-                document.getElementById('example3').innerHTML = formatSteps(ex3);
-            }
-
             // インタラクティブデモ
             function calculateDemo() {
                 const base = parseFloat(document.getElementById('baseInput').value);
@@ -831,7 +816,7 @@ <h3>🎯 実際の計算比較</h3>
 
 <div style="color: #ffb74d; margin: 10px 0;">✅ 高速指数演算：</div>
 2^7 = 2 × 2^6                    (奇数処理)
-2^6 = (2^3)^2 = 8^2              (偶数処理)  
+2^6 = (2^3)^2 = 8^2              (偶数処理)
 2^3 = 2 × 2^2 = 2 × 4 = 8       (奇数処理)
 2^2 = (2^1)^2 = 2^2 = 4          (偶数処理)
 2^1 = 2 × 2^0 = 2 × 1 = 2       (奇数処理)
@@ -862,7 +847,7 @@ <h3>🎯 実際の計算比較</h3>
 Step 1: x = 1/2 = 0.5, n = 4     (負の指数変換)
 Step 2: 0.5^4 を計算
         0.5^4 = (0.5^2)^2         (偶数処理)
-        0.5^2 = 0.25              
+        0.5^2 = 0.25
         0.5^4 = 0.25^2 = 0.0625
 
 <div style="color: #4caf50; margin: 15px 0; padding: 10px; background: rgba(76, 175, 80, 0.1); border-radius: 5px;">