overloaded functions can get translated to invalid python

[ashleyh]

Contrived example:

def print_type(int x):
    print('int')

def print_type(x):
    print('unknown')

translates to

def print_type(x):
    def print_type1(x):
        print('int')

    def print_type2(x):
        print('unknown')

    if isinstance(x, int):
        return print_type1(x)
    elif : # <--- invalid syntax
        return print_type2(x)
    else:
        raise TypeError("Invalid argument types")

(comment added by me)