Block Integer parsing of a string if it contains a decimal point.

[JaredDavis22]

Small change improved the performance of the code for my usage.

Does the current code handle decimal numbers with a comma?

eg 10,001 for 10.001

This change will do nothing for those cases.

Quick test below showing the impact of generating the exception.

    public static void main(String[] args) {
        double[] doubles = {1.4, 1.8, 100.56, 3438535,43534545.67575 ,};
        int[] ints = {14, 18, 10056, 34385,43534545 ,};
        final long startTime = System.nanoTime();
        String[] parseThis = new String[doubles.length*2];
        int count =0;
        int good = 0;
        for (int x = 0; x < doubles.length; x++) {
           parseThis[x] = String.valueOf(doubles[x]);
           parseThis[x+ doubles.length] = String.valueOf(ints[x]);
        }
        for (int i = 0; i < 700000 ; i++) {
            try {
                String p = parseThis[i % 10];
                int dot = p.indexOf('.');
                if (dot == -1) {
                    Integer.parseInt(p);
                    good++;
                }
            } catch (NumberFormatException e) {
                // eat it
                count++;
            }
        }
        final long elapsed = System.nanoTime() - startTime;
        System.out.println("stop. good="+good+" exceptions=" + count+ " time="  + elapsed/1000000000.0);
    }

stop. good=350000 exceptions=0 time=0.022590425

change one line

    int dot = p.indexOf('X');

stop. good=350000 exceptions=350000 time=0.436176896